Quick Trig Question: Solving for θ=-Pi/4

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SUMMARY

The discussion centers on solving for θ in the equation θ = Tan-1(-2/2), which simplifies to θ = -π/4. The tangent function is restricted to the range of -π/2 to π/2, making the angle -π/4 valid. Participants emphasize the importance of a solid understanding of basic trigonometry and its functions, particularly for calculus applications involving integrals and trigonometric substitutions.

PREREQUISITES
  • Basic trigonometry concepts, including the unit circle
  • Understanding of inverse trigonometric functions
  • Familiarity with the tangent function and its properties
  • Knowledge of calculus, particularly integrals and trigonometric substitutions
NEXT STEPS
  • Review the unit circle and its relationship to trigonometric functions
  • Study inverse trigonometric functions, focusing on their ranges and values
  • Learn about trigonometric substitutions in calculus
  • Explore educational resources on Khan Academy, specifically the trigonometry section
USEFUL FOR

Students in calculus, particularly those struggling with trigonometry concepts, as well as educators seeking to reinforce foundational trigonometric principles for their students.

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Homework Statement


I am working through a calc 2 problem. I managed to get here without really completely understanding trig. There was a point in the problem where θ=Tan-1(-2/2) = -Pi/4. How does this work?

Homework Equations


I do not know any relevant equations


The Attempt at a Solution


I really have no clue. I have done research countless times.
 
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For purposes of the Inverse Tangent, the Tangent function is restricted to the angle values from negative pi/2 to positive pi/2. A tangent of (-2/2) is the same as the tangent of (-1), and just relating this to the unit circle, this ange is -π/4.
 
mrshappy0 said:

Homework Statement


I am working through a calc 2 problem. I managed to get here without really completely understanding trig. There was a point in the problem where θ=Tan-1(-2/2) = -Pi/4. How does this work?
I would advise you to spend some time reviewing basic trigonometry, especially in relation to the trig functions and their inverses. If you are trying to work through integrals without a solid understanding of trig, you will really have a hard time, particularly when it comes to trig substitutions.

Some time invested in reviewing your old precalc book would really pay off. Alternatively, there are many helpful videos about a variety of topics in math at khanacademy.org. A good place to start would be http://www.khanacademy.org/#trigonometry.
 

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