Remainder when (1!+2!+3!+...+100!)^2 is divided by 5

stamenkovoca02 · Mar 17, 2021

1.The remainder when dividing (1!+2!+3!+...+100!)^2 by 5 is?
5 divides evenly into 5!, 6!, 7!, ..., 100!. It would also divide evenly into things like 2!*8! or 20!*83!, but not 4!*3!
but whether then ^2 affects the rest?
And what is answer?Thanks

cbarker1 · Mar 17, 2021

You have to show some type of attempt. We can't provide the answer, but we can guide you to the answer.

Remainder when (1!+2!+3!+...+100!)^2 is divided by 5

Discussion

Undergrad Is infinity a necessary concept?

High School Ant on a stretchy rope puzzle

High School Potato paradox

Undergrad Descartes’ Geometry of Square Roots

High School Does this equation (Einstein’s field equations in general relativity) equal 12?

Mathematica NDSolve with forcing function via "digital waveguide"

MATLAB Unable to produce desired results using state-space model with observer for inverted pendulum

Insights Revisiting the Velocity-Time Function

Insights Remote Operated Gate Control System

Insights AI Enriched Problem Solving

Insights Thinking Outside The Box Versus Knowing What’s In The Box

Insights Why Entangled Photon-Polarization Qubits Violate Bell’s Inequality

Insights Quantum Entanglement is a Kinematic Fact, not a Dynamical Effect

Remainder when (1!+2!+3!+...+100!)^2 is divided by 5

Discussion

Similar threads

Undergrad What is the remainder when (x^3 +1)/(x^2 +3) is divided by (x^3 +1)/(x^2 +3)?

Undergrad What is the Correct Quotient and Remainder When Dividing this Polynomial?