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Research on learning abilities of mice

  1. Mar 29, 2009 #1
    1. The problem statement, all variables and given/known data

    We want to test the learning abilities of mice. We put them in a maze. If they choose to go to the right, they will find food. If they go to the left, there's nothing.

    Assuming that P(right) = P(left) = 0.5 the first try, P(right) = P(left) = 0.5 the second try given that the mouse chooses left the first try, and P(right) = F the second try given that the mouse chooses right the first try - what is the chance that the mouse chose right in the first try, given that it chose right in the second try?

    2. Attempt

    [tex]
    P(A|B) = \frac{P(B \cap A)}{P(A)} = \frac{F / 2}{1/2}= F
    [/tex]

    Correct answer: [tex]\frac {2F}{2F+1}[/tex]
     
  2. jcsd
  3. Mar 29, 2009 #2
    Check your formula for the conditional probability, there should be a P(B) in the denominator.
     
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