Resoance states and quark annihilation

[Master J]

I've been looking at interactions between K mesons and "ordinary" matter such as protons and neutrons.
Since I can't put a bar over a letter, I'll let a CAPITAL letter stand for an ANTI-quark.

sD + duu ---> suu + uU (thru a resonance baryon suu ++) I know this one is possible, but what about the following?

sD + duu ---> duu + sD here the d and D annhilate and give a d D again. Why would a u and U be prefered? Because they are lighter? At high energy, would we get a d D as above?


Again, I know this one happens:

sU + udu ---> sdd + uD (virtual n exchange)

what about a resonance state at the right centre of mass energy (CME) (resonance particle being sdu)?

I guess my question is...CAN a resonance particle, and thus annihilation occur once we have the right CME? And when we are away from the CME different possible interactions can occur?





Are such interactions possible? I don't see why not...I'd guess they all are, yet with different branching fractions.

 

[Meir Achuz]

In physics, anything that can happen, does happen, so your last statement is correct. A resonance will occur at the resonance energy, but this can be a broad range of energies due to the width of the resonance.