Riemann tensor expressed using metric and derivatives

[Jogging-Joe]

TL;DR

Could someone please write out or post a link to the Riemann Tensor written out solely in terms of the metric and its first and second derivatives--i.e. with the Christoffel symbol gammas and their first derivatives not explicitly appearing in the formula.

Could someone please write out or post a link to the Riemann Tensor written out solely in terms of the metric and its first and second derivatives--i.e. with the Christoffel symbol gammas and their first derivatives not explicitly appearing in the formula.

Thanks.

 

[Haborix]

This link has both the Riemann tensor and the Christoffel symbols. I am not inclined to retype everything just to substitute one into the other. Where are you headed with this? Even if you could find such an expression prechurned on the internet, it is one of those things I would not trust to be error free.

 

[Jogging-Joe]

Thanks.

I know that a person can get the Riemann Tensor in the form I want by substituting the metric and its first derivatives into the Christofell gammas in the standard Riemann Tensor formula.. As you noted, it is easy to make errors and that is why I would not trust me doing it, and would want a second opinion calculation. Someone must have put it in that form, somewhere.

 

[martinbn]

Thanks.

I know that a person can get the Riemann Tensor in the form I want by substituting the metric and its first derivatives into the Christofell gammas in the standard Riemann Tensor formula.. As you noted, it is easy to make errors and that is why I would not trust me doing it, and would want a second opinion calculation. Someone must have put it in that form, somewhere.

But why do you want it in that form?

 

[Jogging-Joe]

I can show that Birkhoff's Theorem is wrong, and I think I might be able to prove it in a second independent way, which would require me to use that particular form of the Riemann Tensor.

 

[PeterDonis]

I can show that Birkhoff's Theorem is wrong

No, you can't. You may think you can, but you've made an error somewhere.

I think I might be able to prove it in a second independent way, which would require me to use that particular form of the Riemann Tensor.

Sorry, we don't help people with personal theories on this site, particularly personal theories which we already know are wrong (see above).

Thread closed.