- #1
ryan8642
- 24
- 0
u and v are contained in V
Lets say the scalar multiplication is defined as:
ex.
ku=k^2 u or ku = (0,ku2) u=(u1,u2)
does this mean that this is also the same for different scalar m?
mu=m^2 u or mu = (0,mu2) u=(u1,u2)
and does this mean the same for any vector v
kv=k^2 v or kv = (0,kv2) v=(v1,v2)
Is this correct?
Axioms 7,8,9 contain the 2 different scalars as well as vectors. it really confuses me.
Can someone please put me on the right track :s
Lets say the scalar multiplication is defined as:
ex.
ku=k^2 u or ku = (0,ku2) u=(u1,u2)
does this mean that this is also the same for different scalar m?
mu=m^2 u or mu = (0,mu2) u=(u1,u2)
and does this mean the same for any vector v
kv=k^2 v or kv = (0,kv2) v=(v1,v2)
Is this correct?
Axioms 7,8,9 contain the 2 different scalars as well as vectors. it really confuses me.
Can someone please put me on the right track :s