Understanding the Schrodinger Equation and 1/2 Spin in Quantum Mechanics

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SUMMARY

The discussion centers on the Schrödinger equation and the concept of spin in quantum mechanics. The Schrödinger equation serves as the quantum equivalent of Newton's Second Law, describing the evolution of a wavefunction ψ, where |ψ|² represents the probability density of a particle's position. Spin 1/2 refers to a specific measurement of spin-angular momentum, quantified in units of \hbar, indicating that possible outcomes of spin measurements are half-integers of \hbar, such as 1/2, 3/2, and 5/2.

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Swankie
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Hi all,

In class I've recently been taught the Schrödinger equation and about spin(couple weeks apart). My questions are-

1. In laymans terms, what exactly does the S-eqn mean? What I have taken it to be so far, is an equation that determines the probability of the position of an e- in "orbit" around the nucleus

2. I get the full integer 1,2,3... spin, but what exactly does it physically mean to have 1/2 spin?

I searched a bit for clear answers but have come up with nil so far =)
 
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The Schrödinger equation is the quantum analogue of Newton's Second Law. It describes the evolution of a wavefunction ψ, where we intepret |ψ|2 as the probability density function for the particle.
 
spin 1/2 is just a number. Its the spin-angular momentum measured in units of \hbar. That is, \hbar /2=5.272859\times 10^{-35}\;\text{joule}\cdot\text{sec}. If something has spin 1/2 or half-integer spin it means the possible outcomes of measurements of spin for that thing are half-integers of hbar, like, 1/2, 3/2, 5/2, etc...
 

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