1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Selectivity of free radicals in halogenation.

  1. May 20, 2013 #1
    Hi, can anyone please explain what selectivity of free radicals is? For example, there is an MCAT question that I recently came across and that can't seem to make sense of the answer.

    Which of the following halogens will give the greatest percent yield of tertiary alkyl halide when reacted with isobutane in the presence of heat or light?
    a. F2
    b. Cl2
    c. Br2
    d. Isobutane wont produce a tertiary alkyl halide

    The answer is C. Br2, but i dont understand why... I applying common sense. Here is what I thought it would work. F is the least selective and the most reactive when is in the free radical form. My common sense tells me that since is very reactive and less selective, it won't care what carbon it binds to, so the tertiary hydrogen in isobutane (which is surrounded by 3 alkyl groups, or 9 hydrogens), will also react with F. Br and Cl are both less reactive and more selective. Hence they will most likely bind to the other primary carbons cause they are readily there. But this seems to not have been the right approach, can you please help me out? Starting by what selectivity is...

    Thank you.
  2. jcsd
  3. May 20, 2013 #2


    User Avatar
    Gold Member

    Fluorine is well, fluorine. You simply don't mess with it. The only products you will see is CF4 and HF.

    As for Chlorine, the hierarchy between primary, secondary and tertiary is not wide. But since the probability of formation of primary halide is 0.9 (you can realize this) which is very high, you get primary halide with Chlorine as major product.

    But in case of Bromine, the hierarchy is very very wide. Bromine prefers reacting with tertiary Carbon around 1800 times more than primary carbon, so even if the probability of formation of tertiary halide is 0.1, the tendency of formation increases its productivity nonetheless.
  4. May 21, 2013 #3
    thank you, but still dont understand about selectivity... :(
  5. May 22, 2013 #4


    User Avatar
    Gold Member

    Selectivity is experimentally determined. We can only give suitable explanations. This depends upon the kinetics of the reaction. And you may know, the rate of the reaction can only be determined experimentally.

    This is some data that I was taught. Hopefully this will help you. You can estimate the major product by using this term "Productivity", a product of relative reactivity and collision probability leading to formation of that compound.

    For chlorine, relative reactivity is : Primary is (1), Secondary is (3.9) and Tertiary is (5).
    For bromine, relative reactivity is : Primary is (1), Secondary is (80) and Tertiary is (1800).

    Try finding the productivity of Primary and Tertiary Chloride and Bromide and see which halogen will tend to form which product as major one.

    *I can't guarantee the authenticity of this method. But it worked for me.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted