Show that d²y/dx² / (dy/dx)⁴ is constant for x = t³+1, y = t²+1

  • Thread starter Thread starter squenshl
  • Start date Start date
  • Tags Tags
    Parametric
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
squenshl
Messages
468
Reaction score
4

Homework Statement


A curve is defined by the parametric equations ##x=t^3+1## and ##y=t^2+1##.
Show that ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant.

Homework Equations

The Attempt at a Solution


So you differentiate both equations wrt ##t## then apply the chain rule to get ##\frac{2}{3t}##. Applying the chain rule after differenating twice to get ##\frac{d^2y}{dx^2}=\frac{1}{3t}##.
Substitute in both to get the result?
 
Physics news on Phys.org
squenshl said:

Homework Statement


A curve is defined by the parametric equations ##x=t^3+1## and ##y=t^2+1##.
Show that ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant.

Homework Equations

The Attempt at a Solution


So you differentiate both equations wrt ##t## then apply the chain rule to get ##\frac{2}{3t}##. Applying the chain rule after differenating twice to get ##\frac{d^2y}{dx^2}=\frac{1}{3t}##.
Substitute in both to get the result?
Yes. Keep in mind that ##\frac{d^2 y}{dx^2} = \frac d {dx} \left(\frac {dy}{dx}\right) \cdot \frac {dt}{dx}##, using the chain rule.
 
Mark44 said:
Yes. Keep in mind that ##\frac{d^2 y}{dx^2} = \frac d {dx} \left(\frac {dy}{dx}\right) \cdot \frac {dt}{dx}##, using the chain rule.
Got it thanks a lot
 
Last edited: