Simple Hyperplane Equation - What am I Missing?

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SUMMARY

The discussion centers on finding the equation of a hyperplane H in R4 that passes through the point P(3,-4,1,-2) and is normal to the vector u=[2,5,-6,-3]. The correct form of the hyperplane equation is derived as 2x1 + 5x2 - 6x3 - 3x4 + 14 = 0, leading to the conclusion that k should equal -14, not -26 as initially stated. The confusion arises from a potential typo in the problem statement, as the calculations confirm the derived equation.

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cowmoo32
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I'm trying to learn linear algebra using Schaum's outline and this is one of the practice problems:

Find and equation of the hyperplane H in R4 that passes through P(3,-4,1,-2) and is normal to u=[2,5,-6,-3]

The equation is in the form 2x1+5x2-6x3-3x4 = k

They say to substitute P into the equation to obtain k=-26 but I keep coming up with k=-14. This is simple math but I'm clearly missing something. Where am I going wrong?
 
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It's probably a typo.
 
Let X be a point in the hyperplane. Then u.(X-P)=0 should be your equation.

So, 2(x1 - 3) + 5(x2 + 4) - 6(x3 - 1) - 3(x4 + 2) = 0

2x1 + 5x2 - 6x3 - 3x4 + 14 = 0

Same answer you get. Is there a typo somewhere?
 
There has to be a typo because the next problem is similar and the answer there is correct.
 

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