Sin(t) - cos(t) can be rewritten as?

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SUMMARY

The expression sin(t) - cos(t) can be rewritten as sqrt(2)cos(3PI/4 - t). This transformation utilizes the equation Re^(xt)cos(bt - angle), where R is calculated as sqrt(A^2 + B^2). The confusion arises from the cosine property cos(-x) = cos(x), which explains the switch of 3PI/4 with t in the final expression sqrt(2)(cos(t - 3PI/4)).

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spj1
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The problem:

sin(t) - cos(t) can be rewritten as ? - The answer is sqrt(2)cos(3PI/4 - t).

there is an equation Re^(xt)cos(bt - angle).
R = sqrt(A^2+B^2)

So i get the following answer:

sqrt(2)(cos(t - 3PI/4)).


Why does the correct answer have the 3PI/4 switched with the t??
 
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If you remember the graph of cosine, the property should come to mind that:
cos(-x)=cos(x), which is what's being used here.
 

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