Solve Linear Combinations: -9 - 7x - 15x^2

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SUMMARY

The discussion focuses on solving the polynomial equation -9 - 7x - 15x^2 as a linear combination of the polynomials p1 = 2 + x + 4x^2, p2 = 1 - x + 3x^2, and p3 = 3 + 2x + 5x^2. To find constants a, b, and c, participants suggest two methods: substituting three distinct values for x to generate equations or equating the coefficients of corresponding terms from both sides of the equation. Both methods lead to a system of three equations that can be solved for the unknowns a, b, and c.

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  • Understanding of polynomial expressions and their coefficients
  • Familiarity with linear combinations of functions
  • Basic algebraic skills for solving systems of equations
  • Knowledge of polynomial degree and term comparison
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hi there, my book didn't have an example like this so I am not sure what to do to solve it. Please explain how to do it, thanks.

Express the following as linear combinations of p1 = 2 + x + 4x^2, p2 = 1 - x + 3x^2, and p3 = 3 + 2x + 5x^2

a.) -9 - 7x - 15x^2
 
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You multiply p1 by some constant a, p2 by a constant b, p3 by a constant c. Then comparing the coefficients of the different degrees of x with the polynomial you're trying to get, you have three equations with three unknowns, so you solve for a, b and c
 
a(2+x+4x^2)+ b(1- x+ 3x^2)+ c(3+ 2x+ 5x^2)= -9- 7x- 15x^2

Solve for a, b, and c so that is true for all x.

There are two ways to do that. One is, since this must be true for all x, to choose three values for x, thus getting 3 equations to solve for a, b, and c. The other is to use the fact that, in order for two polynomials to be equal for all x, "corresponding coefficients" must be equal. Setting corresponding coefficients equal here, again, gives you three equations to solve for a, b, and c.
 

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