- #1

Monoxdifly

MHB

- 284

- 0

A. \(\displaystyle -\frac34\)

B. \(\displaystyle -\frac12\)

C. 0

D. 1

E. 3

Dividing p(x) by \(\displaystyle x^2+1\) by \(\displaystyle x^2+1\) with –5a + 4b as the remainder using long division, I got (4bx – 1) – ((a – 1)x + a – 1) = –5a + 4b, thus (4b – a + 1)x + a = –5a + 4b. Does this mean that 4b – a + 1 = 0 since the right hand doesn't have an x term? Or do I need to look for the value of x first? I'm at a loss here.