Solve Stoichometry: Al + HCl to get 1g H2

[Jim4592]

Homework Statement

Elemental (metallic) aluminum (Al) is reacted with HCl to yield aluminum chloride (AlCl3) and hydrogen gas (H2). How many grams of metallic aluminum would be required to produce 1 gram of pure hydrogen gas?

Homework Equations

Al + HCl --> AlCl₃ + H₂

Balance Reaction: 2 Al + 6 HCl --> 2 AlCl₃ + 3 H₂

The Attempt at a Solution

let Z = the amount of Al needed

Z g Al * (1 mol Al / 26.98 g Al) * (3 mol H₂/2 mol Al) * (2.02 g H₂/1 mol H₂) = 1 g H₂

(6.04764 * Z) / 53.96 = 1

Z = 8.922 g Al

I was hoping someone could look over this and see if did the correct process and came up with the right answer.

Thanks!

 

[salva]

You're correct