Solve Word Problem: Becky Had 216 Stamps

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Homework Help Overview

The problem involves a word scenario where three individuals, Becky, Ada, and Cathy, have a certain number of stamps. The original poster expresses confusion about setting up the equations based on the relationships between the number of stamps each person has, particularly focusing on Becky, who initially has 216 stamps.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to establish relationships between the number of stamps using percentages and ratios, but struggles with the algebraic manipulation needed to isolate Becky’s initial count. Some participants suggest substituting values to simplify the equations, while others point out potential errors in the original poster's calculations.

Discussion Status

Participants are actively engaging with the problem, offering guidance on how to substitute variables and solve for Becky’s stamp count. There is a recognition of differing interpretations of the equations, with some participants noting discrepancies in the calculations leading to different results.

Contextual Notes

The original poster is working under the constraints of a homework problem, which may limit the methods they can use to approach the solution. There is also a focus on ensuring that all three individuals end up with the same number of stamps after certain transactions.

Taylor_1989
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I got the word problem off the internet, just for a bit of practice, and get slightly lost towards the end. It tells me becky had 216 stamps, the thing is I am not to sure how to set up the equation I will show my working below.


Ada, Becky and Cathy had some stamps. Cathy had 20%more stamps than Ada. Cathy had 75% as many stamps as Becky. Becky gave 45 stamps to Ada and Cathy in the ratio of 4:1 so that all three girls will have the same number of stamps.

a) How many stamps did Becky have at first?

1. C=A*120\% C=B*75\%

2. ratio \frac{45}{5}=9 9*4=369*1=9

3. B-45=C+9=A+36

This is the point of confusion, I am not quite sure how to solve for B. I know I should some how sub 1 into 3 to make the equation, but not to sure how? could someone point me in the right direction, to how to solve this.

I did convert the percentages to fraction: \frac{6}{5} and \frac{3}{4} but still did not help.

Would really apprecaite the guidence
 
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From this point, all you need to do is substitute .75B for C and solve for B, forgetting about A, though you can check to make sure you got it right by solving for all of the final stamp counts.
 
bossman27 said:
From this point, all you need to do is substitute .75B for C and solve for B, forgetting about A, though you can check to make sure you got it right by solving for all of the final stamp counts.

If I solve for B I get 207, I should be getting 216

Here is how I did it, I personally can't see where I am going wrong, but obviously I am somewhere: B-45=\frac{3}{4}B+9 \rightarrow 4(B-45)=3(B+9) \rightarrow 4B-180=3B+27 \rightarrow B=207
 
B - 45 = .75B + 9

.25B = 54 \Rightarrow B = 216

Your problem was that you solved it as though it was:

B - 45 = \frac{3}{4}(B+9)

and \frac{3}{4}(B+9) \neq \frac{3}{4} B + 9
 
Got it, thanks for that fella; been bugging me all day.
 

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