Solving Complex Equations Involving a,b,c,p,q,r

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juantheron
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Homework Statement



If [tex]\mathbf{a,b,c,p,q,r}[/tex] are complex number

Homework Equations


and [tex]\displaystyle\mathbf{\frac{p}{a}+\frac{q}{b}+\frac{r}{c} = 1+i}[/tex]

and [tex]\displaystyle\mathbf{\frac{a}{b}+\frac{b}{q}+\frac{c}{r} = 0}[/tex].Then find value of

[tex]\displaystyle\mathbf{\frac{p^2}{a^2}+\frac{q^2}{b^2}+\frac{r^2}{c^2}=}[/tex]


The Attempt at a Solution



No idea
 
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juantheron said:

Homework Statement



If [tex]\mathbf{a,b,c,p,q,r}[/tex] are complex number

Homework Equations


and [tex]\displaystyle\mathbf{\frac{p}{a}+\frac{q}{b}+\frac{r}{c} = 1+i}[/tex]

and [tex]\displaystyle\mathbf{\frac{a}{b}+\frac{b}{q}+\frac{c}{r} = 0}[/tex].
I think you have a mistake in the equation above. I believe it should be
[tex]\frac{a}{p}+\frac{b}{q}+\frac{c}{r} = 0[/tex]

I made that change and was able to get a value of 2i for the expression you want to evaluate. What I did was to square both sides of the equation whose right side is 1 + i. If you work with the other equation, as corrected above, you can substitute it in the other equation to arrive at a simplified result.
juantheron said:
Then find value of

[tex]\displaystyle\mathbf{\frac{p^2}{a^2}+\frac{q^2}{b^2}+\frac{r^2}{c^2}=}[/tex]


The Attempt at a Solution



No idea