Solving IVP: Is My Answer Correct?

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SUMMARY

The discussion centers on solving the initial value problem (IVP) represented by the equation ∂u/∂t + 4∂u/∂x = e^(2x) with the initial condition u(x,0) = f(x). The proposed solution u = 1/2 + f(x - 4t) is incorrect for two primary reasons: it fails to satisfy the initial condition u(x,0) = f(x) due to the constant term 1/2, and substituting it back into the differential equation results in 0 instead of the expected e^(2x).

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squenshl
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I had to solve an IVP:
[tex]\partial[/tex]/[tex]u\partial[/tex]t + 4[tex]\partial[/tex]u/[tex]\partial[/tex]x = e2x, u(x,0) = f(x).
I got an answer of u = 1/2 +f(x-4t).
Is this correct and if not, where did I go wrong.
 
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Hard to tell where you went wrong without seeing your work. But it isn't correct for at least two reasons:

1. It doesn't satisfy u(x,0) = f(x) (although it would without the 1/2).
2. If you plug it into the DE you get 0, not e(2x).
 

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