- #1

karush

Gold Member

MHB

- 3,269

- 5

Solve IVP

$y''-y=0;\quad y_1(t)=e^t,\quad y_2(t)=\cosh{t}$

$\begin{array}{lll}

&\exp\left(\int \, dx\right)= e^x\\

& e^x(y''-y)=0\\

& e^x-e^x=0\\ \\

&y_1(x)=e^x\\

&(e^x)''-(e^x)=0\\

&(e^x)-(e^x)=0\\ \\

&y_2(x)=\cosh{x}\\

&(\cosh{x})''-(\cosh{x})=0\\

\end{array}$

ok there was no book answer so hopefully went in right direction so suggestions...:unsure: