MHB Solving Linear Recurrence Relations

taya
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Solve each of the following linear recurrence relations:
1. t(1)=1 t(2)=4
t(n) - 5t(n-1) + 6t (n-2)= 0 for n>1

2. a(n)=4a(n-1) - 4a (n-2)
with initial conditions a(0) = 4 and a(1)=12

3. t(1)=3 t(2)=3
t(n) + 2t (n-1) + t(n-2) = 0
 
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taya said:
1. t(1)=1 t(2)=4
t(n) - 5t(n-1) + 6t (n-2)= 0 for n>1
Rewrite this as [math]t_{n + 2} - 5t_{n + 1} + 6 t_n = 0[/math]. What is your characteristic equation?

-Dan
 
Hello and welcome to MHB, taya! :D

For future reference, we ask that no more than 2 questions be asked in the initial post of a thread.

In case you find repeated characteristic roots, what form will your general solution take?
 

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