Solving x with a*b*c^3, Pie^2, i & 16

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SUMMARY

The discussion focuses on solving the equation w = a*b*c^3*x*√(π^2 * (i - x^2)^2 + 16 * x^2) / 4*d^2 * (1 - x^2)^2 for the variable x, given the constants. The user attempted to isolate x by multiplying both sides by the denominator and squaring the equation to eliminate the square root, resulting in a fourth-degree polynomial. The complexity of solving fourth-degree polynomials is acknowledged, with reference to a general formula that exists but is noted to be complicated.

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arslan894
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w=a*b*c^3*x*√(pie^2 * (i-x^2)^2 + 16 *x^2)/ 4*d^2 *(1-x^2)^2 I have to find x ,i have the values of all other constants ,
I tried to separate it using partial fraction but I am stuck.
 
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Tedious but,
1) multiply both sides by that denominator:
[tex]4wd^3(1- x^2)= abc^3x\sqrt{\pi^2(i- x^2)+ 16x^2}[/tex]

2) get rid of that square root by squaring both sides:
[tex]16w^2d^y(1- 2x^2+ x^4)= a^2b^2c^6x^2(\pi(I- x^2)+ 16x^2)[/tex]

That is now a fourth degree polynomial- there is a general "formula" for solving such polynomial equations but it is very complicated.
 

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