I Spectroscopy: vibronic and rotational transitions

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In spectroscopy, the highest peaks in the absorption spectrum correlate with the most probable energy transitions, specifically the transition from the vibronic level of the fundamental state to the excited state. This is exemplified by the transition v'' = 0 to v' = 2, which corresponds to the highest peak. Each vibrational level contains multiple rotational sublevels, complicating the identification of the most probable rotational transition within the excited state. The Franck-Condon principle, grounded in the Born-Oppenheimer approximation, facilitates the separation of electronic and nuclear wave functions, aiding in this analysis. Understanding these concepts is crucial for accurately interpreting molecular spectroscopy data.
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In spectroscopy, the highest peaks in the absorption spectrum are those that are associated with the most probable energy transitions in a molecule. The most probable transitions are those in which the best superposition between the wave function of the vibronic level of the fundamental state and the wave function of the vibronic level of the excited state in which the molecule arrives after absorbing radiation occurs: in the image this corresponds to the transition v'' = 0 --> v' = 2, so this transition is associated with the highest peak. However, this is an argument that applies only to vibronic transitions, but each vibrational level in turn has many rotational sublevels (J0, J1, J2, etc.) at which the molecule can arrive. That said, how do you figure out which rotational transition is the most probable, again within the second vibronic level of the excited state?
 
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For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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