Spin of 1p1n Nuclei: Theory & Explanation

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SUMMARY

The discussion focuses on the spin states of 1 proton-1 neutron (1p1n) nuclei, specifically examining the ground states of deuteron, 18F, and 50V. The deuteron exhibits a ground state of 1+, while 18F also has a 1+ ground state despite both nucleons occupying the same d5/2 orbital. The nuclear force's spin-dependence is highlighted as a critical factor influencing these states, with the spin-1 configuration being energetically favorable for the deuteron. The inquiry seeks to understand the theoretical framework governing the 1p1n structure.

PREREQUISITES
  • Understanding of nuclear physics concepts, particularly spin states
  • Familiarity with the nuclear force and its spin-dependence
  • Knowledge of nuclear shell models and orbital configurations
  • Basic principles of quantum mechanics as they apply to atomic and nuclear systems
NEXT STEPS
  • Research the nuclear shell model and its implications for nucleon configurations
  • Study the spin-dependence of nuclear forces in detail
  • Explore the theoretical frameworks for 1p1n nuclei and their ground states
  • Investigate the properties and decay modes of 18F and its nuclear structure
USEFUL FOR

This discussion is beneficial for nuclear physicists, students studying nuclear structure, and researchers interested in the theoretical aspects of nucleon interactions and spin states in 1p1n nuclei.

zhangguoqiang
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I am interested in the topic of the thread
https://www.physicsforums.com/showthread.php?t=768539
,especially for those unpair 1p1n case.

As I know, for the simplest case deuteron, the Jπ (groundstate here and later) is 1+ but 0+.
This is very different to the atomic physics case. For He atom, 2 electron create the 1S0 groundstate.
For 18F, it is again 1+, although n and p are in the same orbital d5/2, which can combine the possible 0+,1+,2+,3+,4+,5+.
For 50V is 6+.

Could someone help to explain? Is there theory for the 1p1n structure?
 
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Yes. The nuclear force is spin-dependent, so for the deuteron, the spin-1 state is lower than the spin-0 (which isn't even bound).
 
Thanks, for 18F, is the same reason?
 

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