MHB Stationary Points of x-2xsinx: 0-3pi

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The discussion focuses on finding the stationary points of the function x - 2x sin x within the interval [0, 3π]. The differentiation leads to the equation 1 - 2x cos x - 2 sin x = 0, which cannot be solved analytically. Participants suggest using numeric root-finding methods, like the Newton-Raphson method, to approximate the critical values. The conversation emphasizes the need for numerical solutions due to the complexity of the equation. Overall, the approach to solving for stationary points involves advanced mathematical techniques.
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what are the stationary points of x-2xsinx in the interval of [0,3pi]
i differentiated it and let it equal to 0 . i get when i let 1-2x cosx-2sinx equal 0 i can't solve it
 
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You've differentiated correctly, and it appears to me you will have to use a numeric root finding method, such as the Newton-Raphson method to approximate the critical values. :D
 

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