Steady-state vector of infinite markov chain

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SUMMARY

The discussion focuses on the analytical solution of the steady-state vector for an infinite Markov chain represented by a banded transition probability matrix M. The matrix M has a specific structure where elements "P" and "Q" are arranged in a shifting pattern. It is established that constructing a finite stochastic matrix requires setting the bottom-right element to Q. The steady-state probabilities can be derived by solving the equation Mx=x, leading to a recurrence relation that resolves into a geometric series. The key inquiry is about calculating the limit value of the sum of the steady-state vector elements as n approaches infinity.

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pokey909
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Today we encountered a problem with markov chains and are wondering if this can be solved analytically.

Suppose we have a banded transition probability matrix M of the following form:
M=
[
P P 0 0 0 ...
Q 0 P 0 0 ...
0 Q 0 P 0 ...
0 0 Q 0 P ...
0 0 0 Q 0 ...
. . . . .
. . . . . ]

So with the exception of column 1, all others are equal. The "P 0 Q" element is only shifted one down (or row-wise, "Q 0 P" is shifted to the right).
It is impossible to construct a stochastic matrix with finite size unless you set the bottom-right element to Q.
When this is done, a good approximation of the real solution can be obtained by calculating the eigenvectors of the matrix or just raising it ot high powers.

Generally I am only interested in the sum of the steady-state vector elements.
So I am wondering if the evolution of M^n with n goin from 1 to infinity can be expanded into a series for which limit values are known.

Does anyone know a way to exactly calculate the limit value of the sum of the steady-state vector?
 
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The steady-state probabilities can be found by solving Mx=x. For your example this produces a recurrence relation whose solution is a geometric series.
 

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