Stoichiometry to find the concentration of O2?

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SUMMARY

The discussion focuses on calculating the concentration of dissolved oxygen (O2) using stoichiometry in a Winkler titration experiment. The participants detail two trials involving sodium persulfate (Na2S2O8) and sodium thiosulfate (Na2S2O3) for titration. In Trial 1, 8.7 mL of Na2S2O8 was used at 22°C, while Trial 2 required only 2.55 mL at 0°C. The reactions involved include the oxidation of Mn2+ to MnO2 and the subsequent titration of iodine with thiosulfate, highlighting the importance of understanding the stoichiometric relationships in these reactions.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Familiarity with Winkler titration methodology
  • Knowledge of sodium persulfate and sodium thiosulfate roles in redox reactions
  • Basic principles of molarity and concentration calculations
NEXT STEPS
  • Study the Winkler method for measuring biological oxygen demand (BOD)
  • Learn about the stoichiometric calculations for redox reactions
  • Explore the chemical properties and reactions of sodium persulfate
  • Investigate the role of iodine in titrations and its interaction with thiosulfate
USEFUL FOR

Chemistry students, environmental scientists, and laboratory technicians involved in water quality analysis and oxygen demand measurements will benefit from this discussion.

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2 Mn2+ + O2 + 4 OH- -> 2 MnO2 + 2 H2O
***** Use the stoichiometry of the chemical reaction to calculate the concentration (mg/L) of O2(aq) and concentration of O2 (aq) (Molarity).
DI Water (22 degrees C)
Initial Buret Reading: 20.0ml
Final Buret Reading: 28.7 ml
Volume Na2S2O8 to reach the equivalence point: 8.7ml

I would appreciate any help, thanks!

This is what I have done:
1 mol O2 (2mol MnO2/1 mol O2) * (1 mol I2/1 mol MnO2) * (2 mol S2O3^-2/1 mol I2)= 4 mol S2O3^-2

0.00500 Na2S2O3 (0.0087L)= 4.35*10^-5/4mol= 1.0875 * 10^-5

---------------0.00500 M Na2S2O3 standard solution
---------------II. MnO2 (s) + 2I¯ + 4H+---> Mn2+ + I2 (aq) + 2H2O
III. 2S2O32- + I2 (aq) ---> S4O62-+ 2I
 
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It is a little bit chaotic, can you explain in more details what the procedure and reactions involved are? Have you used sodium persulfate, or sodium thiosulfate (I guess the latter, unless it was a back titration)?
 
Borek said:
It is a little bit chaotic, can you explain in more details what the procedure and reactions involved are? Have you used sodium persulfate, or sodium thiosulfate (I guess the latter, unless it was a back titration)?

It's a biological oxygen demand experiment-winkler titration. We used sodium persulfate.



We did two trials:
FOR TRIAL 1:
DI WATER (22 C)
VOLUME Na2S2O8 TO REACH EQUIVALENCE PT = 8.7ml
Find the concentration of O2 (aq) (mg/L)
Find the concentration of O2(aq) (Molarity)

TRIAL 2:
DI WATER (0 C)
VOLUME Na2S2O8 TO REACH EQUIVALENCE PT = 2.55ml
Find the concentration of O2 (aq) (mg/L)
Find the concentration of O2(aq) (Molarity)
 
Strange, as far as I was able to check Winkler method calls for thiosulfate to titrate iodine. One starts with Mn2+, it gets oxidized by the dissolved oxygen producing brown precipitate (containing Mn3+ and/or Mn4+), this precipitate after adding sulfuric acid oxidizes iodides to iodine, iodine is titrated with thiosulfate. No place for persulfate.

Can you write equations of reactions that take place during the experiment?
 

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