Suppose there are 2 defectives among 5

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SUMMARY

The discussion centers on a probability problem involving defectives among a set of items. Specifically, it addresses the scenario of identifying 2 defective items among 5 through sequential testing. The conclusion is that a maximum of 3 tests is required to find both defectives. Additionally, the forum participant seeks to calculate the probability of finding the first defective item on the first test, given that the second defective is identified on the third test.

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shinkansenfan
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suppose there are 2 defectives among 5...

suppose there are 2 defectives among 5, test one at a time until you find the 2nd defective, find:

1.you need at most 3 tests
2.given the 2nd defective found at 3rd test, find the p that you find the 1st defective at 1st test.

Thanks.
 
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shinkansenfan said:
suppose there are 2 defectives among 5, test one at a time until you find the 2nd defective, find:

1.you need at most 3 tests
2.given the 2nd defective found at 3rd test, find the p that you find the 1st defective at 1st test.

Thanks.

Forum rules require you to show your work. Tell us what you have done so far, and where you are stuck.

RGV
 

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