The Formation of Salts Through Neutralization Reactions

[ND3G]

Write equations for the neutralization reactions that result in the formation of the following salts:

lithium carbonate
H2CO3 + LiO2 --> LiCO3 + H2O

copper (II) chlorate
2HClO3 + CuO --> Cu(ClO3)2 + H2O

aluminium sulphate
2Al(OH3) + 3H2SO4 + 10H2O --> Al2(SO4)3 * 16H2O

ammonium iodide
20HN3O + 13H2O + 30I2 --> 60NH4I + 20H2O

This is all pretty new to me so could someone take a quick look at this and tell me know if I am doing it correctly? If I understand the process, water is a bi-product of the neutralization process. I also tried to find known acids or bases to base the left side equation off.

 

[symbolipoint]

Your cupric chlorate reaction seems good.
Your lithium carbonate reaction looks like an error.
Try better, \[<br /> H_2 CO_3 \; + \;Li_2 O\; \Rightarrow \;Li_2 CO_3 \; + \;H_2 O<br /> \]

 

[Borek]

Neutralization reaction is a reaction between acid and BASE, not between acid and oxide as you wrote in the first two cases. Ammonium iodide is made when NH3(aq) (or NH4OH, or NH3.H2O, you may see different notations) reacts with HI (hydroiodic acid).

 

[trossi]

i'm taking the same course, i got
lithium carbonate
2 LiOH + H2CO3 = 2 H2O + Li2CO3
copper (II) Chlorate
2 HCl)3+ Cu(OH)2 = 2 H2O + Cu(ClO3)2
aluminum sluphate
3 H2SO4 + 2 Al(OH)3 = 6 H2O + Al2(SO4)3
ammonium iodide
HI + NH4OH = H2O + NH4I

I'm not compleatly sure if these are right but if someone can verify this it would be helpful

 

[Borek]

Looks OK. As I have already signalled earlier - ammonia can be tricky, as it is not necesarilly in the form of NH₄OH.

Or rather it is not in this form for sure, but your prof may want this form.