The Formation of Salts Through Neutralization Reactions

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Discussion Overview

The discussion focuses on the formation of salts through neutralization reactions, specifically examining the chemical equations for various salts, including lithium carbonate, copper (II) chlorate, aluminium sulphate, and ammonium iodide. Participants explore the correct reactants and products involved in these reactions.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant presents equations for the formation of lithium carbonate, copper (II) chlorate, aluminium sulphate, and ammonium iodide, noting that water is a by-product of neutralization.
  • Another participant agrees with the copper (II) chlorate reaction but points out an error in the lithium carbonate reaction, suggesting a different equation.
  • A third participant clarifies that neutralization reactions typically involve an acid and a base, challenging the initial approach that included oxides.
  • A fourth participant provides alternative equations for the same salts, indicating uncertainty about their correctness and seeking verification.
  • A fifth participant acknowledges the correctness of the equations while noting that ammonia can be represented in different forms, which may affect the reaction representation.

Areas of Agreement / Disagreement

Participants express differing views on the correct formulations for the neutralization reactions, with no consensus reached on the equations for lithium carbonate and ammonium iodide. The discussion remains unresolved regarding the best representation of these reactions.

Contextual Notes

There are limitations in the clarity of the definitions used for acids and bases, particularly regarding the representation of ammonia. The discussion also reflects varying interpretations of neutralization reactions, which may depend on the context of the course material.

ND3G
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Write equations for the neutralization reactions that result in the formation of the following salts:

lithium carbonate
H2CO3 + LiO2 --> LiCO3 + H2O

copper (II) chlorate
2HClO3 + CuO --> Cu(ClO3)2 + H2O

aluminium sulphate
2Al(OH3) + 3H2SO4 + 10H2O --> Al2(SO4)3 * 16H2O

ammonium iodide
20HN3O + 13H2O + 30I2 --> 60NH4I + 20H2O

This is all pretty new to me so could someone take a quick look at this and tell me know if I am doing it correctly? If I understand the process, water is a bi-product of the neutralization process. I also tried to find known acids or bases to base the left side equation off.
 
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Your cupric chlorate reaction seems good.
Your lithium carbonate reaction looks like an error.
Try better, [tex]\[<br /> H_2 CO_3 \; + \;Li_2 O\; \Rightarrow \;Li_2 CO_3 \; + \;H_2 O<br /> \][/tex]
 
Neutralization reaction is a reaction between acid and BASE, not between acid and oxide as you wrote in the first two cases. Ammonium iodide is made when NH3(aq) (or NH4OH, or NH3.H2O, you may see different notations) reacts with HI (hydroiodic acid).
 
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i'm taking the same course, i got
lithium carbonate
2 LiOH + H2CO3 = 2 H2O + Li2CO3
copper (II) Chlorate
2 HCl)3+ Cu(OH)2 = 2 H2O + Cu(ClO3)2
aluminum sluphate
3 H2SO4 + 2 Al(OH)3 = 6 H2O + Al2(SO4)3
ammonium iodide
HI + NH4OH = H2O + NH4I

I'm not compleatly sure if these are right but if someone can verify this it would be helpful
 
Looks OK. As I have already signalled earlier - ammonia can be tricky, as it is not necesarilly in the form of NH4OH.

Or rather it is not in this form for sure, but your prof may want this form.
 

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