The maximum area that can be enclosed is 800 square feet.

[ksle82]

Given 80 feet of fencing, what is the maximum area that you can enclose along a wall?

Solution:
L=lenght, W=width, A=area

2L+2W=80 (perimeter) ==> L+W=40 ==> L=40-W

LW=A ==> (40-W)(W)= -W^2+ 40W= A

(dA/dW)=0=-2W+40=0 ==> W=20

W=20, L=20--------------------------------------------------ANSWERS

Is this right? any input would be appreciated.

 

[StatusX]

I would think only three sides would be fence and the other would be the wall.

 

[swears]

Yea, he's right only 3 sides.

 

[ksle82]

Doh!
here's the updated solutions:

L+2W=80 ==> L=80-2W

A=LW= (80-2W)(W)= 80W-2W^2

(dA/dW)=-4W+80=0 ==> W=20, L=40 ---------------------Answers