Thinking about magnetic coercive field

Click For Summary
SUMMARY

This discussion focuses on the coercive fields of neodymium (NdFeB) magnets, specifically highlighting a coercive field of 12,000 Oe (approximately 955 kA/m). To demagnetize such a magnet, an external magnetic field equal to this coercive field must be applied. The relationship between the H-field and B-field is established through the equation H = (1/μ) * B, allowing for the calculation of the B-field in the surrounding vacuum. The discussion emphasizes the need for high power, short-duration methods like capacitor discharge to achieve the necessary induction for magnetization changes.

PREREQUISITES
  • Understanding of magnetic fields and coercivity
  • Familiarity with the hysteresis curve of magnets
  • Knowledge of magnetic permeability and its significance
  • Basic principles of capacitor discharge methods
NEXT STEPS
  • Research the magnetic properties of neodymium magnets and their applications
  • Learn about the hysteresis loop and its implications for magnetization
  • Study the effects of magnetic permeability in different materials
  • Explore capacitor discharge techniques for magnetization and demagnetization
USEFUL FOR

Engineers, physicists, and anyone involved in the design or application of permanent magnets, particularly those working with neodymium magnets and related technologies.

SamBam77
Messages
25
Reaction score
0
I am trying to better understand some concepts in magnetism and I hope that someone here can help clarify a few questions that I have.

I am trying to interpret the meaning of the specific coercive fields of magnetic objects. For the sake of discussion, let’s use neodymium (rare-earth) magnets as an example. These magnets have a very high coercive field. Again, for the sake of discussion let’s say the magnet has a coercive field of 12,000 Oe (~955 kA/m),
http://www.translatorscafe.com/cafe...lator/ampere-per-meter-[A/m]-to-oersted-[Oe]/
This would mean that in order to remove magnetization (take it to the M = 0 line on the hysteresis curve) of the magnet one would need to apply this minimum magnetic field (H-field) strength.

Does it make sense to think about the field outside the magnet? What would the field in the air / vacuum be right outside the magnetic at this point?

If we know that,
H = (1/μ) * B
Where mu is the magnetic permeability of the material, we could find the B-field if we know the H-field (from the coercive field). Of course, this is not value inside the magnet, since there is a magnetization that needs to be accounted for. But in the vacuum surrounding the magnet, there should be a field that we can find.

In the above example, could we say that the magnetic induction field (B-field) need to zero the object’s magnetization would be,
B = μ_0 * H_c
B = (4pi E-7 N/A^2) * (955000 A/m) = about 1.2 Tesla
 
Physics news on Phys.org
Your conversion from A/m to T is about correct because Nb-Fe-B magnets have a permeability around 1. Other materials like AlNiCo have µr >> 1 .

Several fields are defined in permanent magnets. 955kA/m for an Nd-Fe-B is rather the field it offers for the using circuit, not the demagnetizing field which uses to be even bigger and translates to >2T.

This means that the induction needed to make or erase such a magnet can't be attained from a magnetic core and must be created without the help of permeability, by using a huge power for a short duration. The standard method is capacitor discharge, like 1m3 capacitors for 0.1dm3 magnets. In 10ms, it's loud and the cables must be hold firmly.

I suggest you to find material data sheets on manufacturers' websites for the material you want. They give magnetization curves which are rather clear.
 
In my example, I was not considering the field inside the magnetic (be it NdFeB, or whatever), but rather the air/vacuum immediately outside the magnet.

I should clarify that I am not really interested I specific case, but rather a more general understanding of what is going on. I just used NdFeB as an example because I thought using real numbers might clarify the question I was asking.
 
Can anyone else offer some insight?
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 26 ·
Replies
26
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
8
Views
3K