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Titration of strong acid with weak base

  1. Jul 4, 2016 #1
    • Please post readable solutions to your problems, not shaky images impossible to read.
    1. The problem statement, all variables and given/known data
    PrjrEfq.png

    2. Relevant equations
    Henderson-Hasselbalch Equation

    3. The attempt at a solution
    GKxObdC.jpg
    Sorry for the huge picture, but the number says 0.007558 mol. Is my ICE table correct?
    Equation:
    7.42 = 6.85 + log((0.007558-x)/x)
    (0.007558-x)/x = 3.715
    x = 0.00160 mol H+/(0.07483 L + 0.01339 L) = 0.0181 M = [HCl]
    It says it is incorrect, though.
     
  2. jcsd
  3. Jul 4, 2016 #2

    Charles Link

    User Avatar
    Homework Helper

    This one is not difficult, but still requires a couple of equations and several algebraic steps. You do need to show the work more clearly for the helper to be able to give good feedback. I think I figured out the solution, but the Physics Forum rules do not allow the helper to simply furnish the solution.
     
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