Titration of strong acid with weak base

[reminiscent]

Homework Statement

Homework Equations

Henderson-Hasselbalch Equation

The Attempt at a Solution

Sorry for the huge picture, but the number says 0.007558 mol. Is my ICE table correct?
Equation:
7.42 = 6.85 + log((0.007558-x)/x)
(0.007558-x)/x = 3.715
x = 0.00160 mol H+/(0.07483 L + 0.01339 L) = 0.0181 M = [HCl]
It says it is incorrect, though.

 

[Charles Link]

This one is not difficult, but still requires a couple of equations and several algebraic steps. You do need to show the work more clearly for the helper to be able to give good feedback. I think I figured out the solution, but the Physics Forum rules do not allow the helper to simply furnish the solution.