To oxidize and to be oxidized , the same meanings?

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SUMMARY

The discussion clarifies the distinction between "to oxidize" and "to be oxidized," emphasizing that the former refers to a substance gaining electrons from a reducing agent, while the latter involves losing electrons to an oxidizing agent. Zinc (Zn) has a greater tendency to be oxidized than silver (Ag), as evidenced by standard electrode potential tables. The conversation also highlights that while Ag+ can oxidize Zn, elemental Ag does not oxidize Zn, and they do not react chemically when mixed. The thermodynamic relationship is established through the Gibbs free energy equation, confirming that reactions with E > +0.3 V are spontaneous.

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  • Understanding of oxidation and reduction reactions
  • Familiarity with standard electrode potentials
  • Basic knowledge of thermodynamics, specifically Gibbs free energy
  • Ability to interpret electrochemical series and activity series of metals
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  • Learn about standard electrode potentials and how to use them in predicting reaction spontaneity
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Chemistry students, educators, and professionals in fields related to electrochemistry and materials science will benefit from this discussion, particularly those focusing on oxidation-reduction processes and thermodynamic principles.

BaO
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for example: Zn has more tendency to oxidize than Ag, orZn has more tendency to be oxidized than Ag?
 
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BaO said:
for example: Zn has more tendency to oxidize than Ag, orZn has more tendency to be oxidized than Ag?

no they're not the same!

--> to oxidize = to take up electrons from a reducing agent
--> to be oxidized = lose electrons due to an oxidizing agent ( = to reduce)

Remember: an oxidizing agent gets reduced and a reducing agent gets oxidized.
 
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so it should be like this right? : Zn has more tendency to be oxidized than Ag
 
wait! how come my book says Zn has more tendency to oxidize than Ag?
 
Your book probably shows you an activity series that looks something like this: http://www.unr.edu/sb204/geology/mas.html . The higher up a metal is on that list the more readily it will be oxidized. The higher up a metal is on that list the stronger the reducing agent it is. The lower down a metal is on that list the more readily it will be reduced. The lower down a metal is on that list the stronger the oxidizing agent it is.

When you use "oxidize" as a verb, the subject of the verb is being reduced. The direct object of the verb is being oxidized. When you use "reduce" as a verrb, the subject of the verb is being oxidized. The direct object is being reduced.

Silver nitrate oxidizes zinc.

Silver nitrate is being reduced- it the oxidizing agent.

You could also say: Zinc reduces silver nitrate

Zinc is being oxidized- it is the reducing agent.
 
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BaO said:
wait! how come my book says Zn has more tendency to oxidize than Ag?
That is wrong! Can you directly quote the passage/sentence where it says this?

What is the name of the book (and its authors)?
 
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for the serie of metals in oxidation and reduction, a more nobler metal will always oxidize a less nobler metal.

--> thus Ag will oxidize Zn (you can also look this up in a table of standard electrode potentials)
 
sdekivit said:
for the serie of metals in oxidation and reduction, a more nobler metal will always oxidize a less nobler metal.

--> thus Ag will oxidize Zn (you can also look this up in a table of standard electrode potentials)
Actually, this is not what a reduction potential table tells you. And in fact, Ag will not oxidize Zn (nor will Zn oxidize Ag). If you mix Ag and Zn, there will be no real chemical reaction at all; they will most likely form a nearly isomorphous alloy.

However, Ag+ will oxidize Zn, while Zn2+ will not oxidize Ag.
 
Gokul43201 said:
Actually, this is not what a reduction potential table tells you. And in fact, Ag will not oxidize Zn (nor will Zn oxidize Ag). If you mix Ag and Zn, there will be no real chemical reaction at all; they will most likely form a nearly isomorphous alloy.

However, Ag+ will oxidize Zn, while Zn2+ will not oxidize Ag.

BaO: This explains why I used silver nitrate in my example.
 
  • #10
how about this sentence , is it right?
magnesium has a higher tendency to oxidize than does iron?
 
  • #11
Gokul43201 said:
Actually, this is not what a reduction potential table tells you. And in fact, Ag will not oxidize Zn (nor will Zn oxidize Ag). If you mix Ag and Zn, there will be no real chemical reaction at all; they will most likely form a nearly isomorphous alloy.

However, Ag+ will oxidize Zn, while Zn2+ will not oxidize Ag.

I disagree (as for the notation, i meant the ion Ag+).Of course you can see this in a table of standard electrode potentials:

Ag^{+} + e^{-} \longrightarrow Ag \Rightarrow E^{0} = +0.80 V
Zn^{2+} + 2e^{-} \longrightarrow Zn \Rightarrow E^{0} = -0.76 V

The relation with thermodynamics: \Delta G = -nFE And because E = E_{ox} - E_{red} E = +0,80 - -0.76 = +1.56 V (when p = p0 and the concentrations are 1M and T = 298 K) the free Gibbs energy is negative and thus the reaction 2Ag^{+} + Zn \longrightarrow 2Ag + Zn^{2+} will occur spontaneously.

In general when E > +0.3 V there is a spontaneous reaction.
 
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  • #12
BaO said:
how about this sentence , is it right?
magnesium has a higher tendency to oxidize than does iron?

you mean the ions rght, because the elementary metals won't oxidise. Then it also depend on the charge of the iron ion.

But because E^{0} of Mg^{2+} = -2.37 V and of the least oxidizing iron ion Fe^{2+} is already -0.44 V the above statement isn't true.
 

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