- #1

ksukhin

- 34

- 1

I'm having difficulty understanding the trivial solutions for the hyperbolic sin and cos when they equal 0.

I know that cos(x)=0 when ##x= π/2 + πn = (2n+1)π/2##

sin(x) = 0 when ##x=πn##

What about cosh(x) and sinh(x)? Please help