Trivial solution for cosh(x)=0 and sinh(x)=0

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In summary, the trivial solutions for the hyperbolic sin and cos are found by setting cos(x)=0 and sin(x)=0 and solving for x. However, for cosh(x), there are no real solutions that make it equal to zero. For sinh(x), x=0 is the only real solution.
  • #1
ksukhin
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I'm doing Sturm-Loiuville problems and I need to find the eigenvalues for λ

I'm having difficulty understanding the trivial solutions for the hyperbolic sin and cos when they equal 0.

I know that cos(x)=0 when ##x= π/2 + πn = (2n+1)π/2##
sin(x) = 0 when ##x=πn##

What about cosh(x) and sinh(x)? Please help
 
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  • #2
ksukhin said:
I'm doing Sturm-Loiuville problems and I need to find the eigenvalues for λ

I'm having difficulty understanding the trivial solutions for the hyperbolic sin and cos when they equal 0.

I know that cos(x)=0 when ##x= π/2 + πn = (2n+1)π/2##
sin(x) = 0 when ##x=πn##

What about cosh(x) and sinh(x)? Please help
##sinh(x) = \frac{e^x - e^{-x}}{2}##
##cosh(x) = \frac{e^x + e^{-x}}{2}##
Clearly cosh(x) is never zero. It's pretty easy to find the zeroes of sinh(x).
 
  • #3
sinh(x)=0 when x=0.
 

FAQ: Trivial solution for cosh(x)=0 and sinh(x)=0

1. What does it mean for cosh(x) and sinh(x) to have a trivial solution?

Having a trivial solution for cosh(x)=0 and sinh(x)=0 means that there is no value of x that satisfies both equations. In other words, there is no real number that can be substituted for x that makes both cosh(x) and sinh(x) equal to 0.

2. How do you solve for the trivial solution of cosh(x)=0 and sinh(x)=0?

Since there is no real solution for these equations, there is no way to solve for the trivial solution. It is important to note that the domain of both cosh(x) and sinh(x) is all real numbers, so it is not possible to restrict the domain in order to find a solution.

3. Are there any complex solutions for cosh(x)=0 and sinh(x)=0?

Yes, there are infinitely many complex solutions for these equations. In fact, every complex number can be substituted for x to make cosh(x) and sinh(x) equal to 0. However, since the question specifically mentions "trivial" solutions, we are only considering real solutions.

4. Why are the trivial solutions for cosh(x)=0 and sinh(x)=0 important in mathematics?

While the trivial solutions may not have any practical applications, they are important in understanding the behavior of the functions cosh(x) and sinh(x). These solutions show that there are no real values of x that make both functions equal to 0, providing insight into the nature of these functions.

5. Is there a connection between the trivial solutions for cosh(x)=0 and sinh(x)=0 and the unit circle?

Yes, there is a connection between the trivial solutions and the unit circle. The functions cosh(x) and sinh(x) can be expressed in terms of exponentials, which are closely related to the unit circle. This connection helps to understand the behavior of the functions and their trivial solutions.

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