- #1

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I'm having difficulty understanding the trivial solutions for the hyperbolic sin and cos when they equal 0.

I know that cos(x)=0 when ##x= π/2 + πn = (2n+1)π/2##

sin(x) = 0 when ##x=πn##

What about cosh(x) and sinh(x)? Please help

- Thread starter ksukhin
- Start date

- #1

- 34

- 1

I'm having difficulty understanding the trivial solutions for the hyperbolic sin and cos when they equal 0.

I know that cos(x)=0 when ##x= π/2 + πn = (2n+1)π/2##

sin(x) = 0 when ##x=πn##

What about cosh(x) and sinh(x)? Please help

- #2

Mark44

Mentor

- 34,514

- 6,200

##sinh(x) = \frac{e^x - e^{-x}}{2}##

I'm having difficulty understanding the trivial solutions for the hyperbolic sin and cos when they equal 0.

I know that cos(x)=0 when ##x= π/2 + πn = (2n+1)π/2##

sin(x) = 0 when ##x=πn##

What about cosh(x) and sinh(x)? Please help

##cosh(x) = \frac{e^x + e^{-x}}{2}##

Clearly cosh(x) is never zero. It's pretty easy to find the zeroes of sinh(x).

- #3

mathman

Science Advisor

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sinh(x)=0 when x=0.

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