raul_l Messages 105 Reaction score 0 Thread starter Oct 9, 2006 #1 Hi I'm having trouble finding the derivative of this function. [tex]y=x ln (x+\sqrt{1+x^2})-\sqrt{1+x^2}[/tex] This is what I've tried so far, but I seem to be getting nowhere. Attachments eq.gif 17.1 KB · Views: 502
Hi I'm having trouble finding the derivative of this function. [tex]y=x ln (x+\sqrt{1+x^2})-\sqrt{1+x^2}[/tex] This is what I've tried so far, but I seem to be getting nowhere.
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Oct 9, 2006 #2 Hi raul! The nasty part of this is, of course the logarithm part, and possibly rearranging the expression you get afterwards. For starters: What is the derivative wrt. x of [itex]\sqrt{1+x^{2}}[/itex]?
Hi raul! The nasty part of this is, of course the logarithm part, and possibly rearranging the expression you get afterwards. For starters: What is the derivative wrt. x of [itex]\sqrt{1+x^{2}}[/itex]?
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Oct 9, 2006 #4 Why the minus sign??
raul_l Messages 105 Reaction score 0 Oct 9, 2006 #5 Right, no minus sign there.. my bad. However, now I get [tex]\ln(x+\sqrt{1+x^2})[/tex] Is this correct? Attachments eq.gif 3.6 KB · Views: 572
Right, no minus sign there.. my bad. However, now I get [tex]\ln(x+\sqrt{1+x^2})[/tex] Is this correct?