Understanding and Expanding the 2nd Chebyshev Function: Calculation Help

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SUMMARY

The discussion focuses on the calculation and expansion of the 2nd Chebyshev function, denoted as \(\psi(x)\). The formula \(\psi(x) = \sum_{p^k \le x} \ln p\) is established as the basis for calculating \(\psi\) values. An example is provided where \(\psi(10)\) is calculated as \(\ln(2520) = 3\ln2 + 2\ln3 + \ln5 + \ln7\). The method for calculating \(\psi(30)\) is also demonstrated, resulting in \(\psi(30) = 4\log 2 + 3\log 3 + 2\log 5 + \log 7 + \log 11 + \log 13 + \log 17 + \log 19 + \log 23 + \log 29.

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camilus
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I'm a bit confused as to how to calculate the 2nd chebyshev function.

I know [tex]\psi (x) = \sum_{p^k \le x} \ln p[/tex]

but can someone show me how to expand it? Like, do I use for 2^k, 2, 4, 8, 16, 32... for all the [tex]p^k \le x[/tex], same with 3, and 4 and so on?

MW gives the example:

[tex]\psi (10) = \ln (2520) = 3\ln2+2\ln3+\ln5+\ln7[/tex]

how would say, [tex]\psi (30)[/tex] be written?
 
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[tex]\spi(30)[/tex]
Let's see...
[tex]2,4,8,16 < 30[/tex]
[tex]3,9,27 < 30[/tex]
[tex]5,25 < 30[/tex]
[tex]7 < 30[/tex]
[tex]11 < 30[/tex]
[tex]13 < 30[/tex]
[tex]17 < 30[/tex]
[tex]19 < 30[/tex]
[tex]23 < 30[/tex]
[tex]29 < 30[/tex]
so ... [tex]\psi(30) = 4\log 2 + 3\log 3 + 2\log 5 + \log 7 + \log 11 + \log 13 + \log 17 + \log 19 + \log 23 + \log 29[/tex]
 

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