Understanding Neutral Buoyancy: Formulas and Calculations Explained

[ch5112]

Hi Genius..

I have no idea where to start..please help me out with this question.

Please see the attached file, it has question and diagram..

for part (a), i know what it menas by neutral buoyant:
Neutral buoyancy is a condition in which a physical body's mass equals the mass it displaces in a surrounding medium. This offsets the force of gravity that would otherwise cause the object to . An object that has neutral buoyancy will neither sink nor rise.

but from part (b), I am not sure what formulas to use and do calculation..
please help me out in details with explantions and some solutions

Thank you

 

[member 553083]

.For part (b), the formula you need to use is the equation of hydrostatic equilibrium: P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid. To solve this, you will need to know the density of the fluid, which is given in the problem as 1000 kg/m³. You also need to know the acceleration due to gravity, which is 9.81 m/s². Now, you know that the object has neutral buoyancy, so the pressure at the bottom of the object, at a depth of 2 meters, is equal to the pressure at the top of the object, at a depth of 0 meters. This means that you can equate the two pressures for the equation of hydrostatic equilibrium. That is, P = ρgh. Plugging in the values from the problem, you get: 1000 kg/m³ * 9.81 m/s² * 2 m = 19620 Pa. This is the pressure at the bottom of the object. The pressure at the top of the object is the same, so it is also 19620 Pa.