Understanding the Redox Reaction of Lead Acetate in an Electrotic Cell

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SUMMARY

The discussion centers on the redox reaction of Lead (II) Acetate in an electrolytic cell, specifically its conversion to Lead Dioxide (PbO2) and Lead (Pb) at the anode and cathode. The oxidation reaction is represented as Pb2+(aq) + 2H2O(l) → PbO2(s) + 4H+(aq) + 2 electrons, while the reduction reaction is Pb2+(aq) + 2 electrons → Pb(s). The complete redox reaction is 2Pb2+(aq) + 2H2O(l) → PbO2(s) + Pb(s) + 4H+(aq). The acetate ion (C2H3O2-) is confirmed as a spectator ion and does not participate in the reaction.

PREREQUISITES
  • Understanding of redox reactions
  • Knowledge of electrolytic cells
  • Familiarity with Lead (II) Acetate chemistry
  • Basic knowledge of oxidation and reduction processes
NEXT STEPS
  • Study the electrochemical properties of Lead Dioxide (PbO2)
  • Research the role of spectator ions in redox reactions
  • Learn about the applications of Lead (II) Acetate in electrolytic cells
  • Investigate the differences between chlorate and perchlorate cells
USEFUL FOR

Chemistry students, electrochemists, and professionals working with electrolytic cells and redox reactions will benefit from this discussion.

mrjeffy321
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I am trying to write a redox reaction for Lead (II) Acetate electrolytically becoming Lead Dioxde and Lead at the anode and cathod of an electrotic cell.
I am using the redox reaction of Lead Sulfate in a car battery as a model, but mine doesn't look right.

I am not sure if I need to include the Aceate ion in the reaction or not, since nothing happens to it.

Oxidation : Pb+2(aq) + 2H2O(l) ---> PbO2(s) + 4H+(aq) + 2electrons
Reduction: Pb+2(aq) + 2electrons ---> Pb(s)
-------------------------------------------------------------------------
Redox: 2Pb+2(aq) + 2H2O(l) ---> PbO2(s) + Pb(s) + 4H+(aq)

Does that look right?

Or perhaps with the acetate,
2Pb(C2H3O2)2(aq) + 2H2O(l) ---> PbO2(s) + Pb(s) + 4H+(aq) + 2C2H3O2-
 
Last edited:
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mrjeffy321 said:
Redox: 2Pb+2(aq) + 2H2O(l) ---> PbO2(s) + Pb(s) + 4H+(aq)
Does that look right?
Yes, that's correct.
mrjeffy321 said:
2Pb(C2H3O2)2(aq) + 2H2O(l) ---> PbO2(s) + Pb(s) + 4H+(aq) + 2C2H3O2-
2Pb(C2H3O2)2(aq) + 2H2O(l) ---> PbO2(s) + Pb(s) + 4H+(aq) + 4C2H3O2-

You could write it like that if you want to, but it's not necessary since the acetate ion is, like you said, a spectator ion.

Let me guess, using PbO2 electrodes for a chlorate cell?
 
Last edited:
Cesium said:
Let me guess, using PbO2 electrodes for a chlorate cell?
How right you are.
well, actually, for a perchlorate cell, which I will also use for chlorate (its the same cell).
 

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