Understanding the Two Types of Density Operators in Quantum Mechanics

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The discussion focuses on the confusion surrounding two types of density operators in quantum mechanics: the position density operator and the state density operator. The first operator, represented by the delta function, is noted to be non-normalized when summing over multiple terms, leading to questions about its meaning and application. The second operator, involving state vectors, is more straightforward but raises inquiries about the relationship between the two forms. Clarification is sought on whether these operators are equivalent or connected through transformations, with emphasis on the need for a proper understanding of their functional roles. The conversation highlights the complexities of interpreting density operators in quantum mechanics.
Liao Chen
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I'm confused about the two density operators:

\rho=\sum_{i}\delta(r-r_{i}) and \rho=\sum_{i}|\psi_{i}>\rho_{ii}<\psi_{i}|

Is there anyone explaining this question to me? Thanks very much.
 
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The first one is not normalized if your sum has more than one term.
 
arkajad said:
The first one is not normalized if your sum has more than one term.

Thanks a lot. Do you mean the two density operators are the same and connected through some transformations? Could you explain with a little more details?
 
After some thinking I really do not know what the first expression could mean. It does not make any sense to me. If I consider it as an operator, it would act as

(\rho\psi)(x&#039;)=\int \delta(x-x_i)\psi(x)dx=\sum_i\psi(x_i)

which is a number and not a function. For a continuous spectrum the formula should look like

(\rho\psi)(x&#039;)=\int \rho(x&#039;,x)\psi(x)dx

So, where did you get it from?
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA

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