Understanding Vacuum Fluctuations Mathematically

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SUMMARY

This discussion focuses on understanding vacuum fluctuations mathematically, specifically in the context of Quantum Electrodynamics (QED). The vacuum expectation value (VEV) of the square of the electric field is established as being inversely proportional to the fourth power of the length of the cube (l) in which measurements are taken. The electric field operator in QED is represented as E ∼ (a + a†), where 'a' is the annihilation operator and 'a†' is the creation operator. It is concluded that while the vacuum expectation value of the electric field itself is zero ( = 0), the expectation value of its square () is non-zero.

PREREQUISITES
  • Quantum Electrodynamics (QED) fundamentals
  • Understanding of vacuum expectation values (VEV)
  • Familiarity with creation and annihilation operators
  • Basic knowledge of field operators in quantum physics
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Physicists, quantum field theorists, and students of advanced quantum mechanics seeking to deepen their understanding of vacuum fluctuations and their mathematical representations.

quantumfireball
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Vaccum fluctuations?

How to understand vacuum fluctuations mathematically without getting into the virtual particles that is so stereotypical of POP sci articles?
Am i right in saying that the vacuum expectation value of the square of electric field is inversely proportional to the fourth power of l.
where l is the length of the cube in where you are measuring the vev?
 
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here's a simple way to put it in terms of creation/annihilation operators (with all indices/sums suppresed).

In QED the electric field operator is given by (suppressing a bunch of indices and constants, etc):

E\sim (a+a^\dagger)

where 'a' annihilates and 'a^\dagger' creates.

then if <whatever> indicates the vacuum expectation value of 'whatever'

<br /> &lt;E&gt;=0<br />
but

<br /> &lt;E^2&gt;\ne 0<br />
 

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