Vant Hoff factor problem. General chem 2

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SUMMARY

The van't Hoff factor for KCl is established as i = 1.85. To calculate the boiling point elevation of a 0.50 m solution of KCl in water, the formula used is ΔTb = Kb × m × i, where Kb for water is 0.51. After calculating the elevation, which results in 0.47175, it is crucial to add this value to the original boiling point of water (100°C) to find the new boiling point. The common error identified is neglecting to perform this final addition step.

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The van't Hoff factor for KCl is i= 1.85. What is the boiling point of a 0.50 m solution of KCl in water? For water, Kb = 0.51.

I have the equation which i believe is (Delta Tb)= Kb x m x i ??


m= molality... = .50 m
Kb is given 0.51
i is given 1.85


I have to have 5 sig figs and the answer i get is .47175, but that's not right supposedly. What I'm I doing wrong?
 
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Are they asking for the increase in the boiling point...or the NEW boiling point? The formula you have gives you the increase but you have to add the number you get to the original boiling point. So here you would add your answer to the boiling point of water. Common mistake people forgetting the last step...
 

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