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Velocity dependent fermion number?

  1. Sep 5, 2009 #1
    Hi all!
    Just a short question I am wondering about. Take a bound state with some valence and sea level. The momentum distribution of the valence quarks and antiquarks has a very direct interpretation. But what about the fermion density? Say the fermion number of the valence quarks is 4 and for the valence antiquarks its -3 (making up a fermion with fermion number 1). Can I say that the constituents making up the bound state are four quarks and three antiquarks? If so, what if this number depends on the velocity? Is there any physical interpretation for such a behaviour?

    Thank you very much in advance!

    With best regards,
  2. jcsd
  3. Sep 5, 2009 #2

    Vanadium 50

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    A hadron is in an eigenstate of N(q) - N(qbbar). It's not in an eigenstate of N(q) + N(qbbar).
  4. Sep 6, 2009 #3
    Ok, but that depends on if you count the fermion number of antiparticles with a plus or a minus? Anyway, what about the velocity-dependence?

    Thank you!
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