Velocity dependent fermion number?

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SUMMARY

The discussion centers on the interpretation of fermion density in bound states, specifically regarding the momentum distribution of valence quarks and antiquarks. The participant, Blue2script, questions whether a bound state with a fermion number of 1, derived from four valence quarks and three valence antiquarks, can vary with velocity. The conversation highlights the distinction between counting fermion numbers of particles and antiparticles, emphasizing that the eigenstate of the fermion number is dependent on the chosen sign convention.

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  • Understanding of quantum chromodynamics (QCD)
  • Familiarity with the concept of bound states in particle physics
  • Knowledge of fermion number conservation
  • Basic principles of momentum distribution in particle physics
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Particle physicists, quantum field theorists, and students studying quantum chromodynamics who are interested in the behavior of fermion densities in bound states and their dependence on velocity.

blue2script
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Hi all!
Just a short question I am wondering about. Take a bound state with some valence and sea level. The momentum distribution of the valence quarks and antiquarks has a very direct interpretation. But what about the fermion density? Say the fermion number of the valence quarks is 4 and for the valence antiquarks its -3 (making up a fermion with fermion number 1). Can I say that the constituents making up the bound state are four quarks and three antiquarks? If so, what if this number depends on the velocity? Is there any physical interpretation for such a behaviour?

Thank you very much in advance!

With best regards,
Blue2script
 
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A hadron is in an eigenstate of N(q) - N(qbbar). It's not in an eigenstate of N(q) + N(qbbar).
 
Ok, but that depends on if you count the fermion number of antiparticles with a plus or a minus? Anyway, what about the velocity-dependence?

Thank you!
Blue2script
 

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