Velocity from position-time graph for dog's motion

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aatari
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Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?
 
Attachments
  • Position vs Time graph: distance (m) against time (s), with segment A rising from 0 to 20 m over 0 to 10 s, flat segment B at 20 m from 10 to 20 s, and segment C falling from 20 m at 20 s to 0 at about 28 s.
    Capture.PNG
    2.5 KB · Views: 801
For c, it looks like he moves 15 meters in 6.667 seconds. Edit: -> It looks like it intersects exactly where those two gridlines meet.
 
TomHart said:
For c, it looks like he moves 15 meters in 6.667 seconds. Edit: -> It looks like it intersects exactly where those two gridlines meet.
So you are saying the dog doesn't go all the to 0? So if that's the case is the velocity then 2.27 m/s?
 
aatari said:
Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?

Position vs Time graph of distance (m) against time (s): line A rises from 0 at t=0 to 20 m at 10 s, B is flat at 20 m until 20 s, and C falls to 0 near 28 s; a blue right triangle is shaded under segment C.

aatari said:
Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?

The y values are 20 m, 20 m and 0 m, but it is more accurate to read Δx and Δy from the blue triangle.
Position vs Time graph of distance (m) against time (s): line A rises from 0 at t=0 to 20 m at 10 s, B is flat at 20 m until 20 s, and C falls to 0 near 28 s; a blue right triangle is shaded under segment C.
 
The dog definitely goes to back to y = 0. I am just saying that the point x=26.6666, y = 5 is a lot easier to read than the point at y=0.
 
Ok that is interesting. Thank you guys!
 
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