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Hey,
Can anyone help me solve this equation please?
Thanks
cos(3θ)=cos^{3}θ-3sin^{2}θcosθ
cos(u+v) = cosu cosv - sinu sinv
sin2u = 2sinu cosu
Can anyone help me solve this equation please?
Thanks
Homework Statement
cos(3θ)=cos^{3}θ-3sin^{2}θcosθ
Homework Equations
cos(u+v) = cosu cosv - sinu sinv
sin2u = 2sinu cosu