The discussion revolves around verifying a trigonometric identity involving the equation cos(3θ) = cos3θ - 3sin2θcosθ. Participants are exploring the properties of trigonometric functions and identities.
The discussion is ongoing, with participants sharing their attempts and approaches. There is a focus on breaking down the left side of the equation, but no consensus or complete solutions have been reached yet.
Participants are working under the constraints of homework rules, which may limit the type of assistance they can provide. There is a repetition of the homework statement, indicating a potential lack of clarity or confusion about the problem setup.
I would start in on the left side.lucy1234 said:Hey,
Can anyone help me solve this equation please?
Thanks
Homework Statement
cos(3θ)=cos3θ-3sin2θcosθ
Homework Equations
cos(u+v) = cosu cosv - sinu sinv
sin2u = 2sinu cosu
Mark44 said:I would start in on the left side.
cos(3θ) = cos(2θ + θ) = ?
I think that's pretty much what I said.iRaid said:cos3x = cos(2x+x) if that helps.