What are the oxidizing and reducing agents in this redox reaction?

[sami23]

H2SO4 (aq) + 2HI (aq) --> SO2 (g) + I2 (s) + 2H2O (l)

Indicate the oxidizing and reducing agents.
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I started by assigning oxidation numbers to all the atoms:
H=+1
O=-2
S=+6 to +4
I=-2 to 0

I think H2SO4 is the reducing agent and 2HI is the oxidizing agent. Is this correct?

 

[sami23]

SO4 oxidizes HI to I2. But what is the reducing agent and are my oxidation numbers for the atoms correct?

 

[Grogerian]

Sulfur gained electrons, and is being oxidized. thus, your reducing agent is H2SO4. I Lost electrons, and thus HI is the oxidizing agent.

this is assuming your oxidation numbers are correct which if i am not mistaken your'e "I" is -1? "H 1+" "I -1" "HI 0"

 

[Borek]

Sulfur gained electrons, and is being oxidized.

OIL - oxidation is loss

I Lost electrons, and thus HI is the oxidizing agent.

RIG - reduction is gain.

this is assuming your oxidation numbers are correct which if i am not mistaken your'e "I" is -1? "H 1+" "I -1" "HI 0"

You can't assign ON to molecule, only to atoms, thus HI doesn't have ON, just (neutral) charge.

I=-2 to 0

For that you will need H²⁺. No such animal.