What is the domain of the given function when expressed in terms of x and y?

  • Thread starter Thread starter soopo
  • Start date Start date
  • Tags Tags
    Domain Function
AI Thread Summary
The domain of the function f(x,y) = (√x + x√y) ∑(k=1 to ∞) (k³ + k) x^k y^k is initially considered to be x > 0 and y > 0. However, the convergence of the infinite series must also be taken into account, suggesting that the domain may be more restricted. The series is always positive, indicating that the function remains real-valued under certain conditions. It is likely that the series converges only within a specific disk centered at the origin, meaning the function could be undefined outside this region. Therefore, determining the exact domain requires analyzing the convergence of the series in relation to x and y.
soopo
Messages
222
Reaction score
0

Homework Statement



What is the domain of the following function?

f(x,y) = (\sqrt(x) + x\sqrt(y)) \sum_{k=1}^{\infinity} (k^3 + k) x^k y^k
when D_f \subset \Re^2.

The Attempt at a Solution



The domain is x>0 \in \Re and y>0 \in \Re in my opinion.
 
Last edited:
Physics news on Phys.org
If f(x, y) were defined only as \sqrt{x} + x\sqrt{y}, that would be correct. However, I think you need to take the summation into account, and determine for which x and y the series converges.
 
Mark44 said:
If f(x, y) were defined only as \sqrt{x} + x\sqrt{y}, that would be correct. However, I think you need to take the summation into account, and determine for which x and y the series converges.

The summation is to infinity.
The sum is always positive so the range is always real.
This would suggests me that x > 0 and y > 0.

However, I am uncertain, since the solution should not be that easy.
 
The sum is probably convergent only for x and y in some disk centered at the origin. Outside that disk the sum would be divergent, hence the function would be undefined. It really seems to me that if you want to find the domain for this function, you need to see which values of x and y are such that the series converges.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top