What is the fragment loss for 51 peak in the given mass spectrum?

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SUMMARY

The discussion centers on analyzing the mass spectrum of a molecule with the formula C9H10O2, specifically focusing on the fragment loss associated with the 51 peak. The identified fragments include 150 (the intact molecule), 122 (loss of C2H2), 105 (loss of C2H5O), and 77 (loss of the entire substituent, resulting in a benzene ring). The participant seeks clarification on the nature of the 51 peak, questioning whether a benzene ring can fragment, given its stability.

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Homework Statement



I'm analysing a mass spectrum I've been given for a molecule with the molecular formula of C9H10O2.

The structure iv deduced is a Benzene ring with COOC2H5 substituent.

so its... Benzene-C(=O)-O-C2H5

I'm working out the fragments shown on the mass spec. Those given to me are 150, 122, 105, 77, 51.

So far, I've deduced:
150 - the molecule as it is
122 - the molecule loses C2H2 (ethene) and leaves an alcohol
105 - the molecule loses C2H5O' (an Ethoxy radical)
77 - the molecule loses the whole substituent of C(=O)-O-C2H5 and leaves an Benzene ring

The problem is, i can't work out the 51 peak? What is lost here? Can a benzene ring be broken - to my knowledge it is stable and hence would not fragment?

Please help me on this :)
 
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