What is the GCD and LCM of 35280 and 4158?

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karush
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Determine
$gcd(2^4 \cdot 3^2 \cdot 5 \cdot 7^2, 2 \cdot 3^3 \cdot 7 \cdot 11)=\boxed{126}$
and
$lcd(2^3 \cdot 3^2 \cdot 5,2 \cdot 3^3 \cdot 7 \cdot 11)=\boxed{83160}$
the number in the box is what W$\vert$A returned
ok i was doing stuff like this about a year ago but forgot
so assume to start
$gcd(35280,4158)$
but can't we take advantage of the powers
 
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prime factorization …

$35280 = 2^4 \cdot 3^2 \cdot 5 \cdot 7^2$
$4158 = 2 \cdot 3^3 \cdot 7 \cdot 11$

greatest common divisor includes the least power of all common factors …
$2 \cdot 3^2 \cdot 7 = 126$

least common multiple includes the greatest power of all common factors and the factors the two values do not have in common …
$2^4 \cdot 3^3 \cdot 5 \cdot 7^2 \cdot 11 = 1164240$
 
Mahalo
so its just choosing the powers then calculate