Where Did I Go Wrong in My Concentration Problem?

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SUMMARY

The discussion centers on a chemistry problem involving the production of lithopone, a pigment formed from the reaction of barium sulfate and zinc sulfide. The user calculated the moles of barium sulfide (BaS) and zinc sulfate (ZnSO4) but incorrectly identified the limiting reagent and the final mass of lithopone produced. The correct answer is 1.93 grams, which requires accurate calculations of the moles of both reactants and their respective molar masses. The key takeaway is the importance of verifying calculations and understanding the concept of limiting reagents in chemical reactions.

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  • Knowledge of molar mass calculations
  • Familiarity with limiting reagents in chemistry
  • Basic proficiency in unit conversions (mL to L)
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Chemistry students, educators, and anyone involved in chemical calculations or laboratory work will benefit from this discussion, particularly those focusing on stoichiometry and reaction mechanisms.

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Homework Statement


hey guys I've got a problem, could you tell us where i went wrong

Lithopone is a brilliant white pigment used in water-based interior paints. It is a mixture of barium sulfate and zinc sulfide produced by the reaction
BaS(aq) + ZnSO4(aq) ZnS(s) + BaSO4(s)
What mass of lithopone in grams (to 3 significant figures) is produced in the reaction of 227 mL of 0.257 M ZnSO4 and 325 mL of 0.280 M BaS?

MY WORKED SOLUTION"
Mole of BaS=0.280*0.325=0.091mole
mole of ZnSO4=0.0257*0.277=0.0712moles <therefore this is limiting

i don't know what i should take the molarmass of to work out the mass?

ANSWER IS 1.93 grams

anyhelp would be GREATFULLY appreciated.



Homework Equations





The Attempt at a Solution

 
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geffman1 said:
mole of ZnSO4=0.0257*0.277=0.0712moles <therefore this is limiting

Check your math. Check it twice, as abvious typo is not the error I am thinking about.

ANSWER IS 1.93 grams

No, 1.93g is not the answer. Probably typo again.

You are on the right track. Find limiting reagent, find moles of both solids that precipitated, find their masses - and as you are looking for a precipitate mass, add them.