Why do molecules not fall apart under observation?

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SUMMARY

The discussion centers on the stability of the H2+ molecule under observation in the context of quantum mechanics, specifically the 1D double well model. The binding energy of the H2+ ion is approximately 2.78 eV, which correlates with the energy of a 450 nanometer wavelength photon. When an electron is observed, the wave function collapses, but the molecule remains intact due to conservation laws preventing dissociation unless the energy exceeds 2.78 eV. The Uncertainty Principle indicates that observing the electron disturbs its state, reinforcing the probabilistic nature of the wave function without implying a definitive location or binding energy at any moment.

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  • Understanding of Quantum Mechanics principles, particularly wave functions and the Uncertainty Principle
  • Familiarity with the 1D double well model in quantum systems
  • Knowledge of binding energy concepts and their relation to photon energy
  • Basic grasp of conservation laws in physics
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  • Study the implications of the Uncertainty Principle on particle observation
  • Explore the concept of binding energy in molecular systems
  • Learn about the effects of photon energy on molecular dissociation
  • Investigate the 1D double well model and its applications in quantum mechanics
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Students and researchers in quantum mechanics, particularly those focusing on molecular physics, as well as anyone interested in the implications of observation on quantum systems.

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Hello

I was just revising for my Quantum Mechanics A exam and was considering the 1D double well model of an H2+ molecule. As I understand it Psi2 is non zero between the wells and therefore there is some negative charge present to which the H+ nuclei are attracted resulting in a covalent bond.

But what happens when the electron is observed and found to be around either of the nuclei? i.e the wave fuction "collapses". Why does the molecule not split apart?

Thanks
 
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First, we need to understand the kinematics of the H2+ ion. Its binding energy is about 2.78 eV (please check this). This is comparable to the energy of a 450 nanometer wavelength photon. So a blue photon could (not will) dissociate an isolated H2+ ion. Macroscopic laws like conservation of energy would prevent dissociation of an isolated ion when the photons are less than 2.78 eV (or longer than 450 nm). The electron cannot be "observed" without disturbing it (per the Uncertainty Principle). The wave function of the 3 particles is nothing more than a probability function; not the kind like rolling snake eyes with two dice. It just implies a fuzzy area where the electron's wave function is (but not where the electron is), but nothing about what its binding energy to either or both protons is at any given time. What can be said is that UV photons could dissociate it by photoelectron emission, but the probability would be based on detailed calculations of the density of final states, and that green light >= 500 nanometers long cannot dissociate it, because of conservation laws.
 

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